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創(chuàng)新互聯(lián)python教程：

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編寫一個 Python 程序來計算數(shù)組中的正數(shù)和負(fù)數(shù)，用于循環(huán)范圍。if 條件(if(posnegarar[I]> = 0))檢查數(shù)組項是否大于或等于零。如果為真，我們在正數(shù)組計數(shù)上加一；否則，將負(fù)數(shù)組計數(shù)加 1。

# Count Positive and Negative in Array

import numpy as np

posNegaArr = np.array([1, -19, -22, 16, -76, 0, 22, 50, -122, 70])
print("posNegaArr Array = ", posNegaArr)

posArrCount = 0
negArrCount = 0

for i in range(len(posNegaArr)):
    if (posNegaArr[i] >= 0):
        posArrCount = posArrCount + 1
    else:
        negArrCount = negArrCount + 1

print("The Count of Positive Numbers in posNegaArr Array = ", posArrCount)
print("The Count of Negative Numbers in posNegaArr Array  = ", negArrCount)

計算數(shù)組中正數(shù)和負(fù)數(shù)的 Python 程序

在這個 Python 示例中，我們使用 for 循環(huán)來迭代實際值，而不是索引位置。在第二個 for 循環(huán)中，numpy greater_equal 函數(shù)檢查特定 numpy 數(shù)組項是否大于或等于零并返回 True。

# Count Positive and Negative in Array

import numpy as np

posNegaArr = np.array([4, 25, -9, 8, -6, -7, 0, 11, -17, 6, -44, 89])
posArrCount = posArrCount1 = 0
negaArrCount = negaArrCount1 = 0

for i in posNegaArr:
    if (i >= 0):
        posArrCount = posArrCount + 1
    else:
        negaArrCount = negaArrCount + 1

print("The Count of Positive Numbers in evennegaArr Array = ", posArrCount)
print("The Count of Negative Numbers in evennegaArr Array  = ", negaArrCount)

print("\n=== Using greater_equal function===")
for i in posNegaArr:
    if (np.greater_equal(i, 0) == True):
        posArrCount1 = posArrCount1 + 1
    else:
        negaArrCount1 = negaArrCount1 + 1

print("The Count of Positive Numbers in evennegaArr Array = ", posArrCount1)
print("The Count of Negative Numbers in evennegaArr Array  = ", negaArrCount1)

計算 Python Numpy 數(shù)組中的正數(shù)和負(fù)數(shù)，用于循環(huán)輸出

The Count of Positive Numbers in evennegaArr Array =  7
The Count of Negative Numbers in evennegaArr Array  =  5

=== Using greater_equal function===
The Count of Positive Numbers in evennegaArr Array =  7
The Count of Negative Numbers in evennegaArr Array  =  5

Python 程序使用 While 循環(huán)計算 Numpy 數(shù)組中的正數(shù)和負(fù)數(shù)。

# Count Positive and Negative in Array

import numpy as np

posNegArr = np.array([418, -22, -33, 0, -89, -56, 11, -99])
i = 0

posArrCount = 0
negArrCount = 0

while (i < len(posNegArr)):
    if (np.greater_equal(posNegArr[i], 0) == True):
        posArrCount = posArrCount + 1
    else:
        negArrCount = negArrCount + 1
    i = i + 1

print("The Count of Positive Numbers in posNegArr Array = ", posArrCount)
print("The Count of Negative Numbers in posNegArr Array = ", negArrCount)

使用 while 循環(huán)輸出 計算正負(fù) Python Numpy 數(shù)組項目

The Count of Positive Numbers in posNegArr Array =  3
The Count of Negative Numbers in posNegArr Array =  5

在這個 Python numpy 數(shù)組的例子中，我們創(chuàng)建了一個函數(shù)(countevenodnumbers(posNegArr))，返回正數(shù)和負(fù)數(shù)的計數(shù)。

# Count Positive and Negative in Array

import numpy as np

def CountEvenOddNumbers(posNegArr):
    posArrCount = 0
    negArrCount = 0
    for i in posNegArr:
        if (np.greater_equal(i, 0) == True):
            posArrCount = posArrCount + 1
        else:
            negArrCount = negArrCount + 1

    return posArrCount, negArrCount

posNegArr = np.array([6, -9, -11, 8, 0, -14, -16, -9, 1])
positive, negative = CountEvenOddNumbers(posNegArr)

print("The Count of Positive Numbers in posNegArr Array = ", positive)
print("The Count of Negative Numbers in posNegArr Array = ", negative)

The Count of Positive Numbers in posNegArr Array =  4
The Count of Negative Numbers in posNegArr Array =  5

分享名稱：Python程序：統(tǒng)計數(shù)組中正數(shù)和負(fù)數(shù)
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