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創(chuàng)新互聯(lián)Python教程：Python怎么從sql提取表名
本篇文章介紹了python使用ply和re模塊提取SQL語句中表名的方法，具有一定的參考價(jià)值，希望對(duì)各位學(xué)習(xí)Python的朋友有幫助！
Python怎么從sql提取表名
ply：詞法語法解析模塊；
re：正則表達(dá)式模塊。
全部代碼如下：
import ply.lex as lex, re
def extract_table_name_from_sql(sql_str):
# remove the /* */ comments
q = re.sub(r"/\*[^*]*\*+(?:[^*/][^*]*\*+)*/", "", sql_str)
# remove whole line -- and # comments
lines = [line for line in q.splitlines() if not re.match("^\s*(--|#)", line)]
# remove trailing -- and # comments
q = " ".join([re.split("--|#", line)[0] for line in lines])
# split on blanks, parens and semicolons
tokens = re.split(r"[\s)(;]+", q)
# scan the tokens. if we see a FROM or JOIN, we set the get_next
# flag, and grab the next one (unless it's SELECT).
result = []
get_next = False
for token in tokens:
if get_next:
if token.lower() not in ["", "select"]:
result.append(token)
get_next = False
get_next = token.lower() in ["from", "join"]
return result
sql2="SELECT a.time_updated_server/1000,content,nick,name FROM " \
"table1 a JOIN " \
"table2 b ON a.sender_id = b.user_id JOIN table3 c ON a.channel_id = c.channel_id JOIN table4 d ON c.store_id = d.store_id WHERE sender_id NOT IN(SELECT user_id FROM table5 WHERE store_id IN ('agent_store:1', 'ask:1')) AND to_timestamp(a.time_updated_server/1000)::date >= '2014-05-01' GROUP BY 1,2,3,4 HAVING sum(1) > 500 ORDER BY 1 ASC"
print(extract_table_name_from_sql(sql2))更多技術(shù)請(qǐng)關(guān)注Python視頻教程。
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